Design and implementation of Honeypot

Problem Statement:
Design and implementation of Honeypot 

PROGRAM

#!/usr/bin/env python

#Name: pyp0t.py

#Version: 0.2

#Author: s3my0n

import time

import socket

def getstuff():

banner = raw_input('\nEnter banner information: ')

host = raw_input('Enter IP Address: ')

while True:

try:

port = int(raw_input('Enter Port Number: '))

except TypeError:

print '\n[-] Error: invalid port number\n'

continue

else:

if (port < 1) or (port > 65535):

print '\n[-] Error: invalid port number\n'

continue

else:

return (banner, host, port)

def writelog(client, data=''):

separator = '='*40

fopen = open('\\home\\potlog.txt', 'a')

fopen.write('Time: %s\nIP Address: %s\nPort: %d\n\n%s%s\n\n'%(time.ctime(), client[0], fopen.close()

def main(host, port, banner):

print '\n[*] Listening ...\n'

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

s.bind((host, port))

s.listen(100)

while True:

(insock, address) = s.accept()

print '[*] Connection from: %s:%d' % (address[0], address[1])

try:

insock.send('%s\n'%(banner))

data = insock.recv(1024)

insock.close()

except socket.error, e:

writelog(address)

else:

writelog(address, data)

if __name__=='__main__':

try:

stuff = getstuff()

main(stuff[1], stuff[2], stuff[0])

except KeyboardInterrupt:

print '\n\n[+] Exiting...'

exit(0)

except BaseException, e:

print '\n[-] Error: %s' % (e)

exit(1)

OUTPUT